9x^2+20x+31=7x+3x-5

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Solution for 9x^2+20x+31=7x+3x-5 equation: 



9x^2+20x+31=7x+3x-5

We move all terms to the left:

9x^2+20x+31-(7x+3x-5)=0

We add all the numbers together, and all the variables

9x^2+20x-(10x-5)+31=0

We get rid of parentheses

9x^2+20x-10x+5+31=0

We add all the numbers together, and all the variables

9x^2+10x+36=0

a = 9; b = 10; c = +36;
Δ = b2-4ac
Δ = 102-4·9·36
Δ = -1196
Delta is less than zero, so there is no solution for the equation

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